Answer: b. increasing returns to scale.
Explanation:
With the high capital costs having enabled decreasing average costs for any conceivable level of demand, the company would be making an increasing returns to scale which means that it would be making more return per capital spent.
This will create a natural monopoly because the company will be more efficient in this particular industry and if another company tried to come in, they would have to spend a lot of money to get to a point of increasing returns to scale.
Answer:
5,500 units
Explanation:
The computation is shown below:
Given that
Need to sell the units in a month = 4,000 units
Beginning inventory = 1,000 units
Desired ending inventory = 2,500 units
So, by considering the above information, the units to be produced is
= Desired ending inventory + need to sell the units in a month - beginning inventory
= 2,500 units + 4,000 units - 1,000 units
= 5,500 units
Answer:
The change in the dollar amount of inventory is $200 due to change in the inventory costing method.
Explanation:
The variable cost per unit is $6.00 while the fixed cost per unit is $2.00
Variable cost per unit = $6.00
Absorption cost pet units = $8.00
Total cost under absorption costing = Absorption cost per unit / number of units in ending inventory
Total absorption cost = $8.00 × 100 = $800
Total cost under variable cost = Variable cost per unit × number of units in ending inventory
Total variable cost = $6.00 × 100 = $600
Change in cost = Total absorption cost - Total variable cost
Change in cost = $800 - $600 = $200
Answer:
n = ㏒ P ÷ ㏒ (1.08)
Explanation:
Compound interest rate
A = P × 
where
P = principal amount (the initial amount you borrow or deposit)
r = annual rate of interest (as a decimal)
A = amount of money accumulated after n years, including interest.
n = number of years
Since we want the principle amount to double i.e., A = 2P
put this in above equation
2P = P × 
divide both sides by P, we get
P = 
put r = 0.08
P = 
P = 
Taking log on both sides
㏒ P =㏒ 
㏒ P = n ㏒ (1.08)
n = ㏒ P ÷ ㏒ (1.08)