1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Irina-Kira [14]
4 years ago
6

sarah teaches craft classes. she has 214 bags of beads. each bag has enough beads for 22 bracelets. she estimates tht since 200

x 20 = 4000 there are enough beads for at least 4000 bracelets. tell how you can critique sarahs reasoning
Mathematics
1 answer:
ANEK [815]4 years ago
6 0
Sarah's reasoning sounds good to start. She rounded the available bags and their content, so the result, 4000 bracelets, should be really easy to reach.

The exact numbers are 214 bags * 22 bracelets / bag = 4708 bracelets; so as you see, Sarah took care of having room to loose some beads and yet the beads will be enough to make 4000 bracelets.

Of course, if you want to be sure, you should ask Sarah some questions. For example:

1) What proportion of beads are normally deffective?

2) What proportion of beads are normally lost when crafting?

So, if Sarah did not take into account those proportions she migth be overestimating the number of bracelets they can make.
You might be interested in
Which set of angles are alternate interior angles
hammer [34]

Hello!

E) 3 and 6

interior angles are the angles on the inside of the parallel angles. In this case, 3, 4,  5, and 6 are interior angles.

<u>alternate</u> exterior angles are 2 interior angles on opposite sides of the line passing through the middle.

in this case, the alternate exterior angles are: 3 and 6 / 5 and 4

choosing from your answer choices, you'll see that the only option that matches either of the 2 alternate interior angles I listed is: E) 3 and 6

I hope this helps, and have a nice day!

5 0
3 years ago
I need help to find the volume
alexira [117]

Answer:

224ft^3

Step-by-step explanation:

l*w*h= volume

5 0
3 years ago
Read 2 more answers
Find the greatest common factor of 65a3b4 and 39a4b5.
natima [27]

Step-by-step explanation: Let's begin by finding the

greatest common factor for the numbers 65 and 39.

I would make a factor tree and break up 65 and 39.

So 65 is 13 x 5 and 39 is 13 x 3.

Since the 13's match up, the greatest

common factor between 65 and 39 is 13.

For the variables, we use the smallest power on each of them.

So we use a^3 and b^4 to get 13a^3b^4 as our GCF.

8 0
3 years ago
A florist uses 225 branches of winterberry to make 75 wreaths. Based on the ratio or unit rate, how many branches of winterberry
kondaur [170]

Answer:

the number of branches required to use 25 wreaths is 75 branches

Step-by-step explanation:

Given that

The florist used 225 branches of winterberry for making 75 wreaths

First we have to compute the unit rate or the ratio

= 225 ÷ 75

= 3 : 1

Now the number of branches required to use 25 wreaths is

= 3 × 25

= 75 branches

Hence, the number of branches required to use 25 wreaths is 75 branches

6 0
3 years ago
Can some one answer this please?<br><br> x - 7 = 13
marshall27 [118]
Add 7 to both sides.
13+7=
20
8 0
3 years ago
Read 2 more answers
Other questions:
  • Find the least common multiple of the following polynomials: 5y^2-80 and y+4
    5·2 answers
  • Ok what is the answer
    13·1 answer
  • Dustin and Melanie are playing a game, where two standard, six-sided number cubes are rolled, and the sum of their outcome is fo
    9·1 answer
  • Divided 21 by the difference between 18 and 9
    11·2 answers
  • 3 1/4 × 4<br><br>I really need help for my extra credit homework
    14·1 answer
  • What’s the volume of the cylinder
    7·2 answers
  • Find the sum 3/10 + 2/5
    10·2 answers
  • A fair coin with sides printed heads and tails is flipped and a golf ball is randomly selected from a bucket that contains 2 yel
    7·1 answer
  • The ratio of 7 days to 13 days
    8·2 answers
  • Select the correct answer.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!