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Lorico [155]
4 years ago
7

What’s the volume of the cylinder

Mathematics
2 answers:
Eduardwww [97]4 years ago
8 0

Answer:753.98


Step-by-step explanation:4^2*15*pie


nevsk [136]4 years ago
3 0

Answer:

188.496 mm^3 (or 188.495559 mm^3 if you need more decimals)

Step-by-step explanation:

We are given the equation of V=pi(r^2)H where V is the volume

To find R, we would look at the circle (or the top in this case). Looking at it we can see that the Diameter is 4mm, we are looking for the radius (or r). To find r, we would take the diameter and divide by 2, we get 2mm

r=2 mm

h= 15mm

v=?

So plugging it into the formula


V=pi*(2^2)*15 = 188.496 mm^3

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The value of
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\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

\sf :\implies x = 1 + \sqrt{2}

So, the value of the fraction is 1 + √2.

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Hope this helps :)
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Step-by-step explanation: :D

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