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Yuki888 [10]
3 years ago
15

A group of art students are painting a mural on a wall. the rectangular wall has dimensions of (6x + 7) by (8x + 5) and they are

planning the mural to be (x + 4) by (2x + 5). what is the area of the remaining wall after the mural has been painted?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0
First: Find x

I used the larger rectangle first but you can do either one.

I added (8x+5) + (8x+5) + (6x+7) + (6x+7) =360

I made the sides equal to 360 because a square’s interior angles are equivalent to 360 degrees.

(8x+5) + (8x+5) + (6x+7) + (6x+7) =360

28x+24 = 360

28x = 336

X = 12

Next: Implement 12 in for x in every equation and follow the formula for a rectangle’s area.

A = b*h

BIG SQUARE:

(8(12)+5) + (8(12)+5) + (6(12)+7) + (6(12)+7)

=360

LITTLE SQUARE:

2((2(12)+5) + (6(12)+7)) = 90

Lastly: Subtract the little squares area from the biggest square

360 - 90 = 270
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An urn contains 7 red marbles and 3 white marbles. three marbles are drawn from the urn one after the other. find the probabilit
vaieri [72.5K]

7+3 = 10 total marbles

 1st pick = 7/10 for a red one

2nd pick = 6/9 reduces to 2/3 for a red one

3rd pick = 3/8 for a white one

7/10 x 2/3 =14/30 reduces to 7/15

7/15 x 3/8 = 21/120 reduces to 7/40

 probability = 7/40

5 0
3 years ago
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
3 years ago
On a team, 8 girls and 7 boys scored a total of 128 points. The difference between the number of points scored by the eight girl
andriy [413]

Answer:

8

Step-by-step explanation:

128-16=112

112÷15(boys+girls)=7.4666666

7.4666666 rounds to 8

7 0
3 years ago
Read 2 more answers
T=m-n for n for the final answer
Snezhnost [94]

Answer:n=-t+m

Step-by-step explanation:

6 0
3 years ago
3) g(x)= x3 + x<br> h(x) = x + 4<br> Find g(0)h(0)
Arte-miy333 [17]

Answer:

goh(x)=x^3+12x^2+49x+68

Step-by-step explanation:

g(x) = x^3+x

h(x)=x+4

We have to find

goh(x)

goh(x) = g(h(x))=g(x+4)

If g(x) = x^3+x

g(x+4) = (x+4)^3+(x+4)

           =x^3+12x^2+49x+68

Hence our answer is

goh(x)=x^3+12x^2+49x+68

4 0
3 years ago
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