The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
Hence, the value of x in x^yz = y^2 is
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Answer:
y=4x-5
Step-by-step explanation:
y-y1=m(x-x1)
y-3=4(x-2)
y=4x-8+3
y=4x-5
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Answer:
[3(x+7)]/4
Step-by-step explanation:
[3(x+7)]/4
Solution
f(r) = 3.14
Now we have to find the area of the circle when the radius (r) = 4.
Plug in r = 4 in f(r) to get the area of the circle.
f(4) = 3.14
f(4) = 3.14 * 4 * 4
f(4) = 3.14 *16
f(4) = 50.24
The answer is C. 50.24
Answer
41/12
Step-by-step explanation:
convert mixed numbers into improper fractions 21/4-(3-7/6)
calculate 21/4 - 11/6
subtract fractions 41/12
