Answer:
-4/5
Step-by-step explanation:
It is upside down, can't see it properly!
Answer:
Given: In triangle ABC and triangle DBE where DE is parallel to AC.
In ΔABC and ΔDBE
[Given]
As we know, a line that cuts across two or more parallel lines. In the given figure, the line AB is a transversal.
Line segment AB is transversal that intersects two parallel lines. [Conclusion from statement 1.]
Corresponding angles theorem: two parallel lines are cut by a transversal, then the corresponding angles are congruent.
then;
and

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.
by Reflexive property of equality:
By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar
therefore, by AAA similarity postulates theorem

Similar triangles are triangles with equal corresponding angles and proportionate side.
then, we have;
[By definition of similar triangles]
therefore, the missing statement and the reasons are
Statement Reason
3.
Corresponding angles theorem
and
5.
AAA similarity postulates
6. BD over BA Definition of similar triangle
3x-y=6, in order to be able to graph this you would have to change the equation to y=, so you need to subtract 3x from that side making it -y=-3x+6, now you need to y positive, so divide both sides by -1, thus making the equation look like y=3x-6, now if you can't plug this into a calculator to see what it would look like then you need to know what y=mx+b means. y is the equation you want to graph obviously, m = the slope, so our slope in this case would be -3, and b = our y intercept, so it would be (0,-6), so plot (0,-6) and use the slope to plot the rest of the points, some other points in this line should include (2,0), (-1,-9) and (4,6), just to name a few. Hope this helps.