(16) (12) (12) is the answer I think
1) Expression 1: 16x^3 y
2) Expression 2: 24 xy^5
Procedure:
1) find the greatest common factor of the coefficients, 16 and 24:
16 = 2^4
24 = (2^3)*3
=> greatest common factor = 2^3 = 8
2) find the greatest common factor of x^3 y and xy^5
That is the common letters each raised to the lowest power:
=> xy
3) Then, the result is 8xy
Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
<u></u>
<u></u>
<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get
After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
R=(3V4<span>Home: Kyle's ConverterKyle's CalculatorsKyle's Conversion Blog</span>Volume of a Sphere CalculatorReturn to List of Free Calculators<span><span>Sphere VolumeFor Finding Volume of a SphereResult:
523.599</span><span>radius (r)units</span><span>decimals<span> -3 -2 -1 0 1 2 3 4 5 6 7 8 9 </span></span><span>A sphere with a radius of 5 units has a volume of 523.599 cubed units.This calculator and more easy to use calculators waiting at www.KylesCalculators.com</span></span> Calculating the Volume of a Sphere:
Volume (denoted 'V') of a sphere with a known radius (denoted 'r') can be calculated using the formula below:
V = 4/3(PI*r3)
In plain english the volume of a sphere can be calculated by taking four-thirds of the product of radius (r) cubed and PI.
You can approximated PI using: 3.14159. If the number you are given for the radius does not have a lot of digits you may use a shorter approximation. If the radius you are given has a lot of digits then you may need to use a longer approximation.
Here is a step-by-step case that illustrates how to find the volume of a sphere with a radius of 5 meters. We'll u
π)⅓
