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sweet-ann [11.9K]
3 years ago
6

The hypotenuse of a right triangle is 4 feet

Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Answer:

514 feet

Step-by-step explanation:

Just simply use the pythagorean thereom:

a^2 +b^2 = c^2

put in the values of a, b, and c with the side lengths of the triangle:

x feet, 64 feet, and x+4 feet

x^2 +64^2 = (x+4)^2 , thus x =510

the hypotenuse = x+4 feet = 510 + 4 = 514

ANSWER: 514 feet

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Problem of the Week (POW) for May 1 - May 8
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Answer:

Becky saves $4.86 by choosing to buy 18 bulbs in the 3 package sets  

Step-by-step explanation:

Becky has 2 options here. She can buy 3 for $4.20 or 2 for $3.34. We can easily determine the prices because both 2 & 3 are factors of 18.

18 / 3 = 6, so multiply 6 * 4.20 to see that 18 bulbs will cost $25.20

18 / 2 = 9, so multiply 9 * 3.34 to see that 18 bulbs will cost $30.06

Now, we can see that buying sets of 3 is cheaper, we need to determine how much we are saving by choosing the cheaper option. (Use subtraction)

$30.06 - $25.20 = $4.86

Becky saves $4.86 by choosing to buy 18 bulbs in the 3 package sets  

4 0
3 years ago
Split 63 into the ratio 4:3
ladessa [460]

Answer:

36 and 27

Step-by-step explanation:

4+3=7

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9x4=36

9x3=27

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PSYCHO15rus [73]

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y=-3x+2

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=-3(x-2)

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From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle
Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ 1\text{ minute } =\frac{1}{60}\text{ degree }

20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}

50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}

By the below diagram,

tan ( 12^{\circ} 50') = \frac{8.20}{y}

tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}

tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}

\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}

Now, again by the below diagram,

tan (31^{\circ}20')=\frac{x}{y}

tan(31+\frac{1}{3})=\frac{x}{y}

\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

8 0
3 years ago
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