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Ok so ummmm idk how to speck in that but well ummmmm idk
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Basically you just count how many there is of each.
So the answers would be:
Pentagon = 1
Triangle = 7
Moon = 1
Hope this helps!
Answer:
C. 238π cm^3.
Step-by-step explanation:
Surface area = 2 * area of the circular ends + area of the curved length
= 2π r^2 + 2π r* l
= 2 π 7^2 + 2π 7 * 10
= 98π + 140π
= 238π cm^3.