Answer:
The function represents a direct variation
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or ![y=kx](https://tex.z-dn.net/?f=y%3Dkx)
In a linear direct variation the line passes through the origin and the constant of proportionality k is equal to the slope m
Let
------> the line passes through the origin
![B(2,10)](https://tex.z-dn.net/?f=B%282%2C10%29)
Find the value of k------> substitute the value of x and y
-----> ![k=10/2=5](https://tex.z-dn.net/?f=k%3D10%2F2%3D5)
![C(4,20)](https://tex.z-dn.net/?f=C%284%2C20%29)
Find the value of k------> substitute the value of x and y
-----> ![k=20/4=5](https://tex.z-dn.net/?f=k%3D20%2F4%3D5)
![D(6,30)](https://tex.z-dn.net/?f=D%286%2C30%29)
Find the value of k------> substitute the value of x and y
-----> ![k=30/6=5](https://tex.z-dn.net/?f=k%3D30%2F6%3D5)
![E(8,40)](https://tex.z-dn.net/?f=E%288%2C40%29)
Find the value of k------> substitute the value of x and y
-----> ![k=40/8=5](https://tex.z-dn.net/?f=k%3D40%2F8%3D5)
The value of k is equal in all the points of the table and the line passes through the origin
therefore
The function represents a direct variation
the equation of the direct variation is equal to
![f(x)=5x](https://tex.z-dn.net/?f=f%28x%29%3D5x)