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laila [671]
3 years ago
15

Is it more efficient from an energy standpoint to be a vegetarian vs. an omnivore?

Biology
1 answer:
lesantik [10]3 years ago
7 0
Vegetarian is the best choice

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Aristotle's model of classification was used until the 1600s. Plants were categorized
Jobisdone [24]

Answer:

some organisms fit into more than one category

Explanation:

Its Right

6 0
3 years ago
Bees pollinate red snapdragons in one part of the garden then fly over to another area and pollinate white snapdragons. After a
VladimirAG [237]
"Disruptive selection" is the one mechanism among the choices given in the question that <span>brought this change in gene frequencies. The correct option among all the options that are given in the question is the fourth option or option "D". I hope that the answer has actually come to your help.</span>
3 0
3 years ago
Which of these organisms is a vertabrate? tulip, horse, slug, or fungus
Tresset [83]
Vertabrate because slug doesn't have bones. it's a slug. fungus is nasty which cuts it out. Tulips are just flowers.
4 0
3 years ago
Are viruses composed of cells?
SashulF [63]

Answer:

No

Explanation:

Viruses are not made out of cells. A single virus particle is known as a virion, and is made up of a set of genes bundled within a protective protein shell called a capsid. Certain virus strains will have an extra membrane (lipid bilayer) surrounding it called an envelope.

4 0
3 years ago
Read 2 more answers
In animals, the inability to make the pigment melanin results in albinism, a recessive autosomal condition. Two unaffected paren
Fittoniya [83]

Answer: 1/16, or approximately 6.25% (see explanation below)

Explanation:

Answering this question requires two steps.

First, we need to figure out the probability that this couple will have a child with albinism in the first place. We know the following:

- Both parents are unaffected.

- The couple has already had one affected child.

- Albinism follows an autosomal recessive inheritance pattern.

Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:

<u>       |      M    |      m   </u>

<u>M    |    MM   |    Mm  </u>

<u>m    |    Mm   |    mm  </u>

Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.

7 0
3 years ago
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