Question

Use the quadratic formula to find the solutions to the

Answer 1

Answer:

D

Step-by-step explanation:

The quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

where a is the coefficient of $x^2$, b being the coefficient of $x$ and c being the constant.

Plug in the values:

$\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}$

$\frac{5\pm\sqrt{-15} }{4}$

Since $\sqrt{-15} =\sqrt{-1} \sqrt{15} =i \sqrt{15}$

The answer is:

$\frac{5\pm i \sqrt{15} }{4}$

Answer 2

Answer: The answer is D.