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alina1380 [7]
3 years ago
11

Cual ecuacion representa un ejemplo de la

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

B) 6(x+2y) + 4 = 6x + 12 y + 4

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Five thousand raffle tickets are sold for $5 each. 50 winnings numbers will be chosen, 40 of which will win $100 each and 10 of
Allisa [31]

Answer:

Step-by-step explanation:

Given

there are 50 winning number out of which 40 get $ 100 each and 10 wins $ 1000 .

let x denotes the winning from a randomly selected ticket

x=100\ with\ Probability\ \frac{40}{5000}

x=1000\ with\ Probability\ \frac{10}{5000}

Expected value is given by

E(x)=100\times \frac{40}{5000}+1000\times \frac{10}{5000}

E(x)=0.8+2=2.8

and Expected return is given by

=100\times \frac{40}{5000}+1000\times \frac{10}{5000}-5

=2.8-5=$ -2.2

5 0
3 years ago
essays Tina Campbell must select and answer four of five essay questions on a test. In how many ways can she do so?
babunello [35]
20 ways hope it helps
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3 years ago
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What is the difference between a ray and line segment line segment is a part of a line bound by multiple points along the line;
koban [17]

A line segment is a part of a line bound by two points; a ray is a line with one endpoint that extends to infinity in one direction. is the difference between a ray and line segment.

Option: C.

<u>Step-by-step explanation:</u>

A line is a set of multiple points that extends from one point to its opposite direction without any end. Ray and Line segments are the two parts that can occur in a line.

A ray is a line with an endpoint in which the line can be extended from that point to infinity in a direction. A line segment also another part line and it consists of two points. Moreover, The line is bounded between those points.

8 0
3 years ago
An event manager recorded the number of people in different age groups that attended a music concert. Which data table accuratel
ch4aika [34]
3rd table I believe
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How to solve for probability
kirill [66]
Solution: The sum of probabilities of all the sample points must equal 1. And the probability of getting a head is equal to the probability of getting a tail. Therefore, the probability of each sample point (heads or tails) must be equal to 1/2. Let's repeat the experiment of Example 1, with a die instead of a coin.
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