Question

At a baseball game, the probability that a fan brings a glove is 0.08. The probability that a fan is left-handed is 0.12. What is the probability that a randomly selected fan has a baseball glove and is left-handed? Round your answer to the nearest hundredth, if necessary.

Answer 1

Let $A$ and $B$ be two events. Then

$P(A \cup B)=P(A)P(B)$.If the events are independent. Here

Let $A=\{a\; fan \;brings\; a \;glove\},B=\{a\; fan \;is\; a \;left-handed\}$.

Then, the probability that a randomly selected fan has a baseball glove and is left-handed is

$P(A \cup B)=0.08*0.12=0.0096$

Answer 2

If the probabilities are independent, the probability that a left-handed person will bring a glove is ...
  0.08×0.12 = 0.0096 ≈ 0.01