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-BARSIC- [3]
3 years ago
14

Divide 30 in a ratio of 3:2

Mathematics
2 answers:
dusya [7]3 years ago
6 0
3+2=5
30 divided by 5=6
6X3=18
6X2=12
18+12=30
18:12
Sergeeva-Olga [200]3 years ago
4 0
Other\ method:\\\\x;y-searches\\\\  \left\{\begin{array}{ccc}x+y=30&|subtract\ y\ from\ both\ sides\\x:y=3:2\end{array}\right\\\left\{\begin{array}{ccc}x=30-y&(1)\\\frac{x}{y}=\frac{3}{2}&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\\frac{30-y}{y}=\frac{3}{2}\ \ \ \ |cross\ multiply\\\\(3)(y)=(2)(30-y)\\3y=60-2y\ \ \ \ |add\ 2y\ to\ both\ sides\\5y=60\ \ \ \ |divide\ both\ sides\ by\ 5\\\boxed{y=12}

Put\ the\ value\ of\ y\ to\ (1):\\x=30-12\\\boxed{x=18}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=18\\y=12\end{array}\right\to18:12}
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Step-by-step explanation:

= \frac{9}{100} × 2005

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3 years ago
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Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
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remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
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if yo want, replace 5^x with a and factor
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take the log₅ of both sides
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5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
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2^x-2=0
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x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
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Answer:

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Step-by-step explanation:

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