Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if hi s square of compost has a side length that is 8 times longer?
2 answers:
64,000 I believe. What I did was find the area so 4*4 =16. 1000/16 = 62.5 earthworms per square foot. So if the side is 8 times longer then 8*4= 32 feet per side and to find the area of that it's 32*32 = 1024 feet squared. So 62.5 * 1024 =64,000
Answer:
The answer is 64000.
Step-by-step explanation:
Given is -
Hiram raises 1000 earthworms in a square of compost 4 ft by 4 ft.
When the square of compost has a side length that is 8 times longer, means the area will increase by a factor of
So, total earthworms will be =
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1) to this case you must match both equations
3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5
now the value of x substitute it in the any of two equations, y = 3(-5)+2 = -13
and the other equation is the same value
y = 2(-5)-3 = -13
the point is ( -5,-13)
