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Ahat [919]
3 years ago
10

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1000 earthworms. How many earthworms can he have if hi

s square of compost has a side length that is 8 times longer?
Mathematics
2 answers:
charle [14.2K]3 years ago
6 0
64,000 I believe. What I did was find the area so 4*4 =16. 1000/16 = 62.5 earthworms per square foot. So if the side is 8 times longer then 8*4= 32 feet per side and to find the area of that it's 32*32 = 1024 feet squared. So 62.5 * 1024 =64,000
Anna11 [10]3 years ago
6 0

Answer:

The answer is 64000.

Step-by-step explanation:

Given is -

Hiram raises 1000 earthworms in a square of compost 4 ft by 4 ft.

When the square of compost has a side length that is 8 times longer, means the area will increase by a factor of 8\times8=64 times.

So, total earthworms will be = 1000\times64=64000

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The complete question is

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