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BARSIC [14]
3 years ago
5

[(2 times 10) divided by 1/3] + 8 =

Mathematics
1 answer:
kondaur [170]3 years ago
3 0

14.6666666667

Step-by-step explanation:

2•10=20/1/3=6.66666666667+8 is that but you can write it like 14.6 with _ that on top

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You and your friend are selling tickets to a charity event. You sell 7 adult tickets and 16 student tickets for $120. Your frien
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4 student tickets
8 adult tickets
6 0
3 years ago
For a quadratic function, which characteristics of its graph is equivalent to the zero of the function? a) y-intercept b) maximu
Sonja [21]

Answer:

d) x-intercept

Step-by-step explanation:

The zeros of a function are the values of x that make y = 0.

Thus, they are the points where the graph crosses the x-axis, that is, the x-intercepts.

a) is wrong. the y-intercept is simply the value of y when x = 0.

b) and c) are wrong. A quadratic can have only one maximum or one minimum; it can't have both. And they are not zeros except in the special case of y = ±ax².

The diagram below is the graph of y = x² + 3x - 46. It shows the zeros at x = -23 and x = 20. The minimum and the y-intercept are not zeros of the function.

3 0
3 years ago
If the line passing through the points (a, 1) and (−17, 8) is parallel to the line passing through the points (0, 5) and (a + 2,
stellarik [79]
Parallel line means the same slope
(8-1)/(-17-a)=(1-5)/(a+2)
so a is 18
4 0
3 years ago
Mason opens a savings account by making a $165.85 deposit. Every week, he deposits another $20.50 in the account. The following
monitta

Answer:

370.85

Step-by-step explanation:

20.50×10. +165.85=

4 0
3 years ago
Read 2 more answers
If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th
VMariaS [17]

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

4 0
3 years ago
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