Answer:
y > 2x - 1
y ≤ 0.5x + 4
Step-by-step explanation:
solid line: (0,4) (-8,0)
m: (0-4)/(-8-0) = -4/-8 = 0.5
b: 4
y = mx + b y = 0.5x + 4
dotted line: (0,-1) (-2,-5)
m = (-5 - -1)/(-2-0) = 2
b = -1
equation: y = 2x - 1
System: y ≤ 0.5x + 4
y > 2x - 1
The equation of a circle with radius r and center at point (a, b) is given by
(x - a)^2 + (y - b)^2 = r^2
1.) For the circle given by x^2 + y^2 = 24
(x - 0)^2 + (y - 0)^2 = (√24)^2
Therefore, center = (0, 0) and radius = √24 = 4.9 units
3.) x^2 + y^2 -10x -2y = -10
x^2 - 10x + (-5)^2 + y^2 - 2y + (-1)^2 = -10 + (-5)^2 + (-1)^2
x^2 - 10x + 25 + y^2 - 2y + 1 = -10 + 25 + 1
(x - 5)^2 + (y - 1)^2 = 16
(x - 5)^2 + (y - 1)^2 = 4^2
2 1/2 + 2 3/5 =
2 5/10 + 2 6/10=
4 11/10 = 5 1/10
5 1/10 - 5 = 1/10
1/10 lb left over
Answer:
yes it is
Step-by-step explanation:
you can never come to a solution that is not -2
