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3 years ago

How would you show algebraically that the quadrilateral with vertices at A(-1, 3) B(3, 5) C(4, 3) D(0, 1) is a rectangle.

Mathematics

2 answers:

max2010maxim [7]3 years ago

4 0

Answer:

c) 3,5

Step-by-step explanation:

maxonik [38]3 years ago

3 0

Answer:

Yoo

Step-by-step explanation:

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A farmer wants to fence in a rectangular area that is 1/8 mile wide by 1/4 mile long. which of the following proportions can the

nikitadnepr [17]

1mi = 5280feet
The first thing you should do in this case is to calculate the perimeter of the rectangle which will be given by:
P = 2 * L + 2 * W
Where
L = long
W = width
Calculating we have:
P = 2 * (1/4) + 2 * (1/8)
P = 1/2 + 1/4
P = 3/4 mi
To calculate this distance to feet we have to use the following expression:
(3/4) / (x) = 1/5280
answer:
 B) 3/4 miles divided by x= 1 mile/5280ft

7 0

3 years ago

Read 2 more answers

Why can you rewrite 4.7 as 4.70

N76 [4]

Because 4.7 is the "abbreviation" for 4.70 also 4.7 is the simplified version of 4.70 kind of like a fraction you 4 70/100 simplified is 4 7/10 or 4.7.

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!

marishachu [46]

Answer:

32m^2

Step-by-step explanation:

32m^2

8*4 = 32

Have a nice day! :-)

6 0

3 years ago

Select the correct answer.

Ratling [72]

I think it’s D but not completely sure!

5 0

2 years ago

Find the length of the segment with endpoints of (3, 2) and (-3, -6).

nevsk [136]

The distance between (3, 2) and (-3, -6) is 10 units

The correct answer is B) 10

Further explanation:

Given points are:

(x1,y1) = (3,2)

(x2,y2)=(-3,-6)

The distance formula is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Putting the values

$d=\sqrt{(-3-3)^2+(-6-2)^2}\\=\sqrt{(-6)^2+(-8)^2} \\=\sqrt{36+64}\\ =\sqrt{100}\\d=10$

The distance between (3, 2) and (-3, -6) is 10 units

Keywords: Magnitude, Distance

Learn more about magnitude at:

#LearnwithBrainly

8 0

3 years ago