How would you show algebraically that the quadrilateral with vertices at A(-1, 3) B(3, 5) C(4, 3) D(0, 1) is a rectangle.
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Hi there! :)
Answer:
---- Starting with: ----
x² - 10x + 24
Since we have a leading coefficient of 1, simply find two numbers that sum up to -10 and multiply into 24.
By guessing and checking, we get the numbers -6 and -4. Put these into factors:
(x - 6)(x - 4)
Therefore, a binomial present in factored form is D. x - 4
