Answer:
9
Step-by-step explanation:
So first I created 2 distance forumlas and set them equal to each other
![\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%285%2B1%29%5E2%2B%28k-2%29%5E2%7D%20%3D%5Csqrt%7B%285-3%29%5E2%2B%28k%29%5E2%7D)
then I simplified them
![(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\](https://tex.z-dn.net/?f=%285%2B1%29%5E2%2B%28k-2%29%5E2%20%3D%285-3%29%5E2%2B%28k%29%5E2%5C%5C)
![36 + k^2 - 4k +4 = k^2 + 4](https://tex.z-dn.net/?f=36%20%2B%20k%5E2%20-%204k%20%2B4%20%3D%20k%5E2%20%2B%204)
![-4k + 36 = 0\\](https://tex.z-dn.net/?f=-4k%20%2B%2036%20%3D%200%5C%5C)
![4k = 36](https://tex.z-dn.net/?f=4k%20%3D%2036)
![k = 9](https://tex.z-dn.net/?f=k%20%3D%209)
when k = 9, the two distances are equal
Answer:
8.25 is the answer.
Step-by-step explanation:
Hope this helps!
Her piece of lace was 80 cm.
2(14)+2(20)+12
28+40+12
=80
Answer:
divide both sides by 3
Step-by-step explanation:
so the answer should be x=3