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ankoles [38]
3 years ago
5

Whats up anybody wanna talk.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

sure i don't have anything to do :)

Step-by-step explanation:

pshichka [43]3 years ago
3 0
Hellooo! How are you tpdya strangers?
You might be interested in
Does anybody know the answer to all of these?
Mama L [17]

Answer:10

Step-by-step explanation:

2+4+6+6+9+13+30=70

70 divided by 7= the mean should be 10

6 0
2 years ago
Read 2 more answers
Ben can type 25 words in half a minute. At this rate, how many words can he type in 5 minutes?
Kruka [31]
I can’t see the “students work”. But the answer would be 250 words in 5 minutes.
Here’s how you would set up the equation:
25x(5*2)=
So your first step would be to multiply 5 and two because they’re in parenthesis, which would be 10.
So now you have:
25x10
25 times 10 is 250.
Hope that makes sense and helps! :)
4 0
3 years ago
Mai is given these two systems of linear equations to solve:
Sholpan [36]

Answer:

Step-by-step explanation:

System 1 has no solution, and System 2 has infinitely many solutions. Wait, YOUR IN HIGH SCHOOL?! IM IN 8TH GRADE AND IM DOING THIS??!! well, idk how to solve this, but these are the answers.

6 0
3 years ago
5. f(x) = 3x³ - 4x² +6x and g(x)=5x ³+ 2x²- 3x. What is f(x) - g(x)?
sasho [114]

Answer:

<h2>A. -2x³ - 6x² + 9x</h2>

Step-by-step explanation:

f(x)=3x^3-4x^2+6x\\\\g(x)=5x^3+2x^2-3x\\\\f(x)-g(x)=(3x^3-4x^2+6x)-(5x^3+2x^2-3x)\\\\=3x^3-4x^2+6x-5x^3-2x^2-(-3x)\qquad\text{combine like terms}\\\\=(3x^3-5x^3)+(-4x^2-2x^2)+(6x+3x)\\\\=-2x^3-6x^2+9x

8 0
3 years ago
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
3 years ago
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