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const2013 [10]
4 years ago
14

1. Write three expressions that are equivalent to 3x+15.

Mathematics
1 answer:
Ipatiy [6.2K]4 years ago
6 0

1 3(x + 5)

(9x + 45 ) / 3

2x + x + 15

2. 6x - 15

2(x + 2x) - 15

2x ( 1 + 2) - 15

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Is -3 a possible solution of –x6 – x3 + 2 = 0?
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Answer:

No

Step-by-step explanation:

The exponents are too far apart for a +2 to make a difference.

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Prove algebraically what type of function this is (even, odd, or neither).<br>f(x) = x^6 – x^4​
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Let's see.

We have function f(x)=x^6-x^4. We have to determine if the function is even or odd or neither.

We can find this out in many ways but the assignment specifically asks to prove this algebraically.

Function is even if f(x)=f(-x), so, x^6-x^4=(-x)^6-(-x)^4

Which is true since negative raised to an even power is positive to that same number.

Similarly, function is odd if f(x)=-f(-x), that is,

x^6-x^4\neq-((-x)^6-(-x)^4).

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Hope this helps.

3 0
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Given the exponential equation 3* = 243, what is the logarithmic form of the equation in base 10? (5 points)
Andrej [43]

Answer:

x = \frac{log\ 243}{log\ 3}

Step-by-step explanation:

Given

3^x = 243

Required

Express as a logarithm

3^x = 243

Take log of both sides

log\ 3^x = log\ 243

Apply the following law of logarithm

log\ a^b = b\ log\ a

So, the expression becomes:

log\ 3^x = log\ 243

x\ log\ 3 = log\ 243

Divide both sides by log 3

\frac{x\ log\ 3}{log\ 3} = \frac{log\ 243}{log\ 3}

x = \frac{log\ 243}{log\ 3}

Hence, the expression in base 10 is:

x = \frac{log\ 243}{log\ 3} or x = \frac{log_{10}\ 243}{log_{10}\ 3}

3 0
3 years ago
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