Answer:
True
Step-by-step explanation:
Why true I had that problem and it was true.
Answer:
No
Step-by-step explanation:
You cant have 2 y values
The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
brainly.com/question/18797214
#SPJ4
An Euler path, in a graph or multi graph, is a walk through the graph which uses every edge exactly once. An Euler circuit is an Euler path which starts and stops at the same vertex. Our goal is to find a quick way to check whether a graph (or multi graph) has an Euler path or circuit.
hope it helps
First, you know that Jackson (let call her J) scored 41 more points than L (Leslie). What we don't know is how many points L scored so we can use a variable that will be 'x'.
So the equation will be
J=41+x.
We also know that the total points is 1,189.
To find out what x is we first subtract
1,189-41. We then get 1,148.
We are now left with 2x and 1,148 so we divide
1,148 by 2 and get 574.
574=x so now we can plug that in.
J= 574+41
Jackson scored 615 points and
Leslie scored 574 points
(You can use bar modeling to do solve this problem. An example of bar modeling is shown below.