Is 10 of 10 of 100 the same as 20 of 100?

the cost of 2 tables and 5 chairs is Rs 2300.if a table costs Rs 30 more than a chair. find the price of each.

Snezhnost [94]

Let us say the price of a table is $x$ and a price of a chair $y$ . Using this terminology we can say that the cost of 2 chairs and 5 tables is $2x+5y=2300$ . We have a second equation though, $x=y+30$ from a table being 30 more than the price of a chair. Using this we can solve the system of equations. I think substitution is the quickest way to do this. Plug x from our second equation into the first equation.

$2(y + 30) + 5y = 2300$

This will simplify to the price of a chair is Rs 320. And add Rs 30 to that and we can find that the price of a table is Rs 350.

It is always good to check. So go ahead and check $(2*350)+(5*320)$ to see that the first equation works (we know the second equation works just by eyeballing. And it looks like the cost is Rs 2300! Hooray!

5 0

2 years ago

I need help!!!!!!!!!

MrRissso [65]

9514 1404 393

Answer:

2. 15 cents/min

3. 7/4 gallon/week = 1.75 gal/wk

Step-by-step explanation:

You want to convert the units without changing the rate. You do this by making use of conversion factors. Each conversion factor has a value of 1, but changes the units. (It has a value of 1 because the quantity in the numerator is equal to the quantity in the denominator.)

In general, you know that when the numerator and denominator of a fraction are the same thing, they cancel, leaving a value of 1. When a variable (or unit) is involved, the cancelled variables (or units) simply disappear.

For example, multiplying (9 dollars)×(100 cents)/(1 dollar) gives ...

$(9\text{ dollar})\times\dfrac{100\text{ cents}}{1\text{ dollar}}=\dfrac{9\times100\times\text{cents}\times\text{dollar}}{1\times\text{ dollar}}=\dfrac{900\text{ cents}}{1}=900\text{ cents}$

The units of "dollar" cancel, leaving cents. Note that we did this by choosing a conversion factor with units we want in the place we want, and units we don't want on the other side of the fraction bar.

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2) We want cents in the numerator, so our conversion factor will be (100 cents)/(1 dollar). And we want minutes in the denominator, so our other conversion factor will be (1 hour)/(60 minutes). Multiplying by these conversion factors, our rate becomes ...

$\dfrac{\$9}{1\text{ hr}}\times\dfrac{100\text{ cents}}{\$1}\times\dfrac{1\text{ hr}}{60\text{ min}}=\dfrac{9\times100\times1\text{ cents}}{1\times1\times60\text{ min}}\\\\=\dfrac{900}{60}\cdot\dfrac{\text{cents}}{\text{min}}=\boxed{15\text{ cents/min}}$

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3) We want gallons in the numerator, so that conversion will be done by (1 gal)/(8 pt). We want weeks in the denominator, so the conversion for that is (7 day)/(1 week).

$\dfrac{2\text{ pt}}{1\text{ day}}\times\dfrac{1\text{ gal}}{8\text{ pt}}\times\dfrac{7\text{ day}}{1\text{ week}}=\dfrac{2\times1\times7}{1\times8\times1}\cdot\dfrac{\text{gal}}{\text{week}}=\boxed{\dfrac{7}{4}\text{ gal/week}}$

7 0

2 years ago

IT COST 859.32 TO HAVE A SCHOOL DANCE A. HOW MANY TICKETS MUST BE SOLD TO COVER THE COST. B HOW MANY TICKETS MUST BE SOLD TO MAK

telo118 [61]

If each ticket is sold for $ 9.20 then you will need to sell 94 tickets to cover the cost of the dance. You will then need to sell 200 tickets to make enough money to cover the dance and to make a profit of $ 980.68

7 0

2 years ago

3^3/3^6 a. 1/27 b 1/9 c 9 d -27 I think the answer is c

STatiana [176]

Answer:

a. 1/27

Step-by-step explanation:

When dividing exponents and the base is the same, we subtract them

x^a/ x^b = x^(a-b)

3^3/3^6

3^(3-6)

3^(-3)