5k-4k=-1+-1
k=-2, its all aboit rearranging the order of numders based on there like terms. If you need any more help ask.
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:
Runner distance time
Arabella 7,299 feet 561 seconds
Bettina 3,425 yards 13 minutes, 12 seconds
Chandra 8,214 feet 0,195 hours
Divya 1,62 miles 732 seconds
To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.
First you need to convert the data to obtain the rate in miles per second.
These are the main conversion identities:
1 mile = 5280 feet
1 mile = 1760 yards
1 hour = 3600 seconds
1 hour = 60 minutes
1 minute = 60 seconds
Arabella:
rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet) =
= 0.00244 mile/second
Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds
Bettina:
13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds
rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds
Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds
Chandra:
rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =
= 0.00222 seconds
Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds
Divya:
rate = 1.62 miles / 732 seconds = 0.00221 seconds
Time = 3.1 mile / 0.00221 seconds = 1403 seconds
Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds
That is equivalent to 2.38 seconds.
Apparent magnitude isn’t the actual brightness, it’s what the brightness appears to be from earth, absolute brightness is the actual brightness an example is our sun it appears bright on earth but in space it is so much more brighter
9514 1404 393
Answer:
5 miles
Step-by-step explanation:
Time/speed/distance problems can be worked a number of ways. Here, we want to know the distance walked. We know the total time and the total distance and the two different speeds. So, we can use a variable to represent the value we want to know: w = distance walked (in miles).
The total time is 9:00 -6:50 = 2:10 = 2 1/6 hours = 13/6 hours.
The total time is the sum of times for the two parts of the trip: walking and riding.
walking time = walking distance/walking speed
= w/3
riding time = riding distance/riding speed
= (20-w)/30
The total time is that given above:
w/3 +(20-w)/30 = 13/6
10w +(20 -w) = 65 . . . . . . . . multiply by 30
9w = 45 . . . . . . . . . . . . subtract 20, collect terms
w = 5 . . . . . . . . . . . divide by 9
The girl walked 5 miles.
Answer: 480
Step-by-step explanation:
