Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.
Answer: 310 centimeters square of paper
Explanation: to find the answer you need to know the surface area of the box. So you use the formula SA = 2ab+2bc+2ac
A=7
B=10
C=5
After inputting the values you get:
SA = 2(7)(10) + 2(10)(5) + 2(7)(5)
and after simplifying:
SA = 140+100+70
SA=310
<span>
f(x)=2^(x-2) = 2^(-4) = 1/2^4 = 1/16
answer
</span><span>A.
f(x)=2^(x-2)</span>
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
Answer:
(-3, 4)
Step-by-step explanation:
let the point P(x, y)
x = (5/7 × (-1+8)) + (-8)
= (5/7 × 7) -8 = 5-8 = -3
y = (5/7 × (8+6)) + (-6)
= (5/7 × 14) -6 = 10-6 = 4
so, P => (-3 , 4)
