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Shalnov [3]
3 years ago
8

How to show work on (-41)+(14)=

Mathematics
2 answers:
Fudgin [204]3 years ago
8 0

Answer:

41-14 so that is 27 so its negative 27 i dont really know how to explain this but yea

Step-by-step explanation:

gladu [14]3 years ago
3 0

-41 + 14 = -( 41 - 14 )

=  41

(-) 14

-----------

   27

------------

-( 41 - 14 ) = -(27) = -27

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In which direction does the graph of the function shown below open?
sp2606 [1]

Answer:

D. Up

Step-by-step explanation:

When a parabola has the form  y=ax^2+bx+c , It is vertical (opens up or down).

Because the variable "x" is squared.

If  "a" is positive, then the parabola opens up, but if it is negative, then the parabola opens down.

In this case you have the quadratic function:

f(x) = 2x^2+5x-4

Which can be rewritten as:

 y = 2x^2+5x-4

Therefore, it is vertical, because it has the form:  y=ax^2+bx+c

You can observe that the value of "a" is:

a=2

Then, since "a" is positive, the parabola opens up.

5 0
3 years ago
ew if you're attracted to those mexican boys with the dirty permed hair and who sags their pants and smell musty too then stay a
nlexa [21]

Answer:

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8 0
2 years ago
PLEASEE HELP AGAINNNN!!!!<br> If a1 = 4 and an = -4an - 1 then find the value of a6
sertanlavr [38]

The 6th term of the geometric sequence is of -4096.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, we have that:

  • The first term is a_1 = 4.
  • a_n = -4a_{n - 1}, hence the common ratio is q = -4.

Thus the 6th term of the sequence is found as follows:

a_6 = a_1q^5 = 4(-4)^5 = -4096

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

6 0
10 months ago
Match each inequality to the correct graph.
inysia [295]

Answer: Hope this helps

4 0
2 years ago
If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
2 years ago
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