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2 years ago

How to show work on (-41)+(14)=

Mathematics

2 answers:

Fudgin [204]2 years ago

8 0

Answer:

41-14 so that is 27 so its negative 27 i dont really know how to explain this but yea

Step-by-step explanation:

gladu [14]2 years ago

3 0

-41 + 14 = -( 41 - 14 )

= 41

(-) 14

-----------

------------

-( 41 - 14 ) = -(27) = -27

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12/k = 18/42 what is k

Maslowich

Answer:

k = 28

Step-by-step explanation:

12/k = 18/42

Cross multiply.

18k = 12 * 42

18k = 504

Divide both sides by 18.

k = 28

5 0

3 years ago

Good morning!

Assoli18 [71]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 2) The integral of a constant follows this rule:

adx = ax

In this case, it is 1dx = 1x

This can be simplified to just x

Add a constant to this, to get the final answer of:

x + C

3) The integrals power rule is:

$x^adx = \frac{x^a^+^1}{a +1}$

Substitute the values in:

$\frac{x^5^+^1}{5 +1}$

This can be simplified to:

$\frac{x^{6} }{6}$

Add a constant to this to get the final answer of:

$\frac{x^{6} }{6} +C$

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

He coordinates of the vertices of a polygon are (−2, −2) , (−2, 3) , (2, 4) , (3, 1) , and (0, −2) .

Nitella [24]

Answer: The perimeter is 17.52

Step-by-step explanation:

1. You can plot the points, as you can see in the graph attached.

2. As you can see in the graph, the points are:

$A(-2,-2)\\B(-2,3)\\C(2,4)\\D(3,1)\\E(0,-2)$

And the lenghts <em>AB</em> and <em>EA</em> are:

$AB=5$

$EA=2$

3. To find the other lenghts, you can apply the formula for calculate the distance between two points:

$distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

4. Thefore, you have:

$BC=\sqrt{(2-(-2))^{2}+(4-3)^{2}}=4.12\\CD=\sqrt{(2-3)^{2}+(4-1)^{2}}=3.16\\DE=\sqrt{(3-0)^{2}+(1-(-2))^{2}}=4.24$

5. The perimeter is:

$P=AB+CD+DE+EA\\P=5+4.12+3.16+4.24+2\\P=17.52$

7 0

3 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

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5 0

1 year ago

Which statement is true about the end behavior of the graphed function?

dexar [7]

As x approaches negative infinity, the graph approaches negative infinity
as x approaches positive infinity, the graph approaches positive infinity

5 0

3 years ago

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