Answer:
Large box weighs 18.25 kilograms
Small box weighs 15.25 kilograms
Step-by-step explanation:
A fruit company delivers its fruit in two types of boxes: large and small.
Let x = weight of large box.
Let y = weight of small box.
A delivery of 3 large boxes and 5 small boxes has a total weight of 131 kilograms. This means
3x + 5y = 131 - - - - - - - - - - -1
A delivery of 6 large boxes and 2 small boxes has a total weight of 140 kilograms.
This means 6x + 2y = 140 - - - - - - - 2
Solving equation 1 and equation 2 by elimination method,
Multiply equation 1 by 6 and equation 2 by 3
18x + 30y = 786
18x +6y = 420
24y = 366
y = 366/24 = 15.25
Put y = 15.25 in equation 1
3x + 5× 15.25 = 131
3x + 76.25 = 131
3x = 131 - 76.25
3x = 54.75
x = 54.75/3 = 18.25
Answer:
<em>Hey mate, here's ur answer:</em>
<em>----------------------------------------------------------</em>
<em>(4a - 3b + 4c) + (8a - 2b + 3c)</em>
=4a+−3b+4c+8a+−2b+3c
=(4a+8a)+(−3b+−2b)+(4c+3c)
<u>=12a−5b+7c</u>
----------------------------------------------------------
<em>Hope it helps</em>
<em>#stayhomestaysafemate</em>
<em>:D</em>
Answer:
x=0
Step-by-step explanation:
Answer:
Step-by-step explanation:
since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.
FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.
Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 
.
Now, Let FD bisect angle ADB,
then ADF = too.
Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX
FDE = ADF + ADE = 
Answer:
try right 3, up 4. if not, try right 4, up 3.
