Answer:
y = (-2/3)x + 31/3
Step-by-step explanation:
The answer is very simple .
First you need to determine the slope, which is the reciprocal of the first line.
Then,
y = mx + b
m => -1/m
The perperdicular line has a new slope equal to m = -1/2
In the formula (y - y1) = m ( x - x1 ) + b , you should sustitude this value.
So the final equation will be
-3 = -1/2 (0) + b
b = - 3
y = (-1/2)x - 3
That is the solution
Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).
y
r = 3 sin g becomes sqrt(x^2+y^2) = 3*-----------------------
sqrt(x^2+y^2)
Squaring both sides,
9y^2
x^2+y^2 = -----------------
x^2 + y^2
If this is correct (and I'm not convinced that it is), then (x^2+y^2)^2 = 9y^2
shows the relationship between x and y. Can anyone improve on this result?
Factor out the common term; 3
(3(x + 1))^2 = 36
Use the Multiplication Distributive Property; (xy)^a = x^ay^a
3^2(x + 1)^2 = 36
Simplify 3^2 to 9
9(x + 1)^2 = 36
Divide both sides by 9
(x + 1)^2 = 36/9
Simplify 36/9 to 4
(x + 1)^2 = 4
Take the square root of both sides
x + 1 = √4
Since 2 * 2 = 4, the square root of 2 is 2
x + 1 = 2
Break down the problem into these 2 equations
x + 1 = 2
x + 1 = -2
Solve the first equation; x + 1 = 2
x = 1
Solve the second equation; x + 1 = -2
x = -3
Collect all solutions;
<u>x = 1, -3</u>
