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Alisiya [41]
3 years ago
15

What I would like to know is how to solve this problem

Mathematics
1 answer:
ratelena [41]3 years ago
3 0
30 - 29 = 1 for the first one.
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
PLEASE HELP ANSWER FAST I WILL GIVE BRAINLIEST!!!!!
bija089 [108]

Answer:

Take the number of weeks as x

12x = 544 - 100

x =444/12

x = 37

Thus it would take her 37 weeks to buy her a laptop

6 0
3 years ago
Read 2 more answers
Please help :) this is exponential decay 10 pts
VMariaS [17]
$50.00 after 0 months and $37.50 after 6 months.
We first must calculate half-life using the attached formula.
Half-Life = (time * ln(2)) / ln (beginning amount/ending amount)
Half-Life = (6 * 0.69314718056) / ln (50.00 / 37.50)
Half-Life = ( <span> <span> <span> 4.1588830834 </span> </span> </span> ) / ln ( <span> <span> <span> 1.3333333333 </span> </span> </span> )
Half-Life = ( <span> <span> 4.1588830834 </span> </span> ) / 0.28768207245
Half-Life = <span> <span> <span> 14.456525038 </span> </span> </span> months

Now we need to calculate "lambda"
lambda = ln(2) / half-life
lambda = 0.69314718056 / <span>14.456525038
lambda = </span><span><span><span>0.0479470121 </span> </span> </span>

Next we have to use this formula:
Ending Amount = beginning amount • e^( -lambda • time )
(where "e" is the mathematical constant 2.718281828...)
Ending Amount = 50 * 2.718281828^<span>(-0.0479470121*24 months)
</span><span>Ending Amount = 50 * 2.718281828^(-1.1507282904)
</span>Ending Amount = 50 * <span> <span> <span> 0.3164062499 </span> </span> </span>
Ending Amount = <span> <span> <span> 15.82</span></span></span> dollars

**********************************************************************
As a DOUBLE-CHECK we can work this out every 6 months:

0 months $50
6 months = $50 - (50 *.25) = 37.50
12 months = $37.50 -(37.50 *.25) = <span>28.125
18 months = $28.125 -(28.125 * .25) = 21.09375 </span>
24 months = $21.09375 -(21.09375 * .25) = <span> <span> <span> 15.8203125 </span> </span> </span>

You'll find this page quite helpful:
http://www.1728.org/halflif2.htm


5 0
4 years ago
Read 2 more answers
Freddy is buying wings and nachos for a party. a box of ten wings cost $7.00 Nachos cost $4.00 per tray. He must spend less than
soldi70 [24.7K]
Hey there! The answer is 7x + 4y < 40

Let's first rearrange our data in a more structured way.

x represents a box of wings which has a cost of $7.00. Therefore the total cost of the boxes is 7x.

y represents a tray of nachos which has a cost of $4.00. Therefore the total cost of the trays is 4y.

The sum of the costs of trays and boxes, which is (7x + 4y) must be smaller than $40.

Now we can set up the inequality.
7x + 4y < 40

~ Hope this helps you!
6 0
3 years ago
Julie tips the ball over the net in a volleyball game. The graph shows the quadratic function that represents the height of the
Andrew [12]

We are given a graph for the height of the ball with respect to horizontal distnace x of the ball from Julie.

From the graph, we can see the position of Julie is at (0,0). And starting height of the ball when thrown is 6 feet.

Then it moved to the maximum height of 14 feet. And hit to the ground when it has position on x-axis is 3.5 feet.

<em>Because we can see the parabola is crossing x-axis at 3.5 on the right.</em>

<em>That represents distance of the ball from Julie when it hit to the ground.</em>

<h3>Therefore, it has a horizontal distance of 3.5 feet from Julie.</h3>
6 0
3 years ago
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