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3 years ago

5

A family of 2 adults and 3 kids go to a play. Admission costs $8 per adult and $5 per kid.What expression would show the total a

dmission cost for the family?

1 answer:

Hitman42 [59]3 years ago

6 0

(2x8)+(2x5) that should be the answer

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Can someone help me find x and y using the 30-60-90 theorem

Fittoniya [83]

X is radical 3
y is 2 radical 3

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3 years ago

Which expression is not equivalent to the other expressions?

Ket [755]

That would be D

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bur D = -12x - 24

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3 years ago

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2 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

3 years ago

Write L if it is likely to happen and U if unlikely to happen.

maria [59]

Answer:

Probabilities

Likely to happen (L) Unlikely to happen (U)

a. 4/5 5/8

b. 3/5 3/8

c. 4/5 4/7

d. 0.3 0.09

e. 5/6 and 4/5 2/3

Step-by-step explanation:

Probabilities in Percentages:

a. The probability of 4/5 = 80% and 5/8 = 62.5%

b. The probability of 3/8 = 37.5% and 3/5 = 60%

c. The probability of 4/5 = 80% and 4/7 = 57%

d. The probability of 0.3 = 30% and 0.09 = 9%

e. The probability of 2/3 = 67% and 4/5 = 80% and 5/6 = 83%

b) To determine the relative values of the fractional probabilities, it is best to reduce them to their fractional or percentage terms. When this is done, the relative sizes become obvious, and then, comparisons can be made.

3 0

2 years ago