$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

Using the law of cosines,

$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$

3 0

1 year ago

A small bowl of candy holds 75% as much as a large bowl of candy.

jekas [21]

Answer:

_____

Step-by-step explanation:

Im pretty sure it would be 45 ____

4 0

3 years ago

-5 = 1 / 3 ( -1 - w )<br> plz help with step by step answer

sweet [91]

Step-by-step explanation:

$- 5 = \frac{1}{3} ( - 1 - w) \\ \frac{1}{3} ( - 1 - w) = - 5 \\ - 1 - w = - 5 \div \frac{1}{3} \\ - 1 - w = - 5 \times 3 \\ - 1 - w = - 15 \\ - w = - 15 + 1 \\ - w = - 14 \\ w = 14$

4 0

3 years ago