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VikaD [51]
2 years ago
11

Solve for x? 9(x+1)=9x+1 A. 0 B. No Solution C. 1 D. All Real Numbers.

Mathematics
1 answer:
Semenov [28]2 years ago
6 0
The answer is d. Because it is the same on both sides
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Solve the system using substitution<br> 8x+9y=15<br> 5x-2y=17
Otrada [13]

5x-2y=17\ \ \ \ |-5x\\-2y=-5x+17\ \ \ \ |:(-2)\\y=2.5x-8.5\\\\\text{substitute to the first equation}\\\\9x+9(2.5x-8.5)=17\ \ \ \ |\text{use distributive property}\\9x+22.5x-76.5=17\ \ \ \ |+76.5\\31.5x=93.5\ \ \ \ |:31,5\\x=3\\\\\text{substitute the value of x to the equation}\ y=2.5x-8.5\\\\y=2.5(3)-8.5=7.5-8.5=-1\\\\Answer:\ x=3,\ y=-1\to(3;\ -1)

8 0
3 years ago
A line passes through the point (–2, 7) and has a slope of –5.
kakasveta [241]

Answer:

it is -7 because the 2 make it like that

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP ASAP!!!<br> (Question and answers pictured)
BARSIC [14]

9514 1404 393

Answer:

  (d)  reflection about the x-axis, up 6 units

Step-by-step explanation:

The parent function y=1/x is multiplied by -1, which reflects it over the x-axis. Then 6 is added, which shifts it up 6 units.

The transformations are ...

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6 0
2 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
Please help me. right answer will get brainliest
Harman [31]

Answer:

I attached the answers :)

Step-by-step explanation:

hope this helps :)

(Its a bit messy becuz i used a mouse to write, sry about that)

8 0
3 years ago
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