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Serggg [28]
2 years ago
5

Help as soon as possible The greatest common factor of y^4. y^6 and y^5 is

Mathematics
1 answer:
olchik [2.2K]2 years ago
6 0

Answer:

Answer:GCF: y^4

Step-by-step explanation:

Factors of:

y^4= (y) (y) (y) (y) = y^4 (1)

y^5 = (y) (y) (y) (y) (y) = y^4 (y)

y^6 = (y) (y) (y) (y) (y) (y) = y^4(y^2)

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How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Fantom [35]
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
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3 years ago
An acute angle ? is in a right triangle with cos ? = nine tenths. what is the value of sec ?? square root of nineteen divided by
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3 years ago
Find the solution of<br> m(-11 + m) = 0
zhuklara [117]

i tried ;w;

Step-by-step explanation:

m(−11+m)=0

Step 1: Simplify both sides of the equation.

m2−11m=0

Step 2: Factor left side of equation.

m(m−11)=0

Step 3: Set factors equal to 0.

m=0 or m−11=0

m=0 or m=11

Answer:

m=0 or m=11

6 0
3 years ago
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What kind of angels is created by the intersection of two perpendicular lines rays or line segments
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8 0
3 years ago
You want to install a 2 yd wide walk around a circular swimming pool. The diameter of the pool is 23 yd. What is the area of the
GrogVix [38]

Answer:

157 square yards.

Step-by-step explanation:

Given:

Width of walk around a circular swimming pool = 2 yard

The diameter of the pool = 23 yard

Question asked:

What is the area of the​ walk ?

Solution:

<em>To find area of walk, we will first calculate area of the pool and then combined area of pool and walk then after we will subtract the area of pool from combined area.</em>

The diameter of the pool = 23 yard

Radius of the pool = \frac{diameter }{2}=\frac{23}{2} =11.5\ yard

Area\ of\ circle=\pi r^{2}

                       =3.14\times(11.5)^{2} \\=3.14\times11.5\times11.5=415.265\ square\ yard

<u>As width of walk around a circular swimming pool is 2 yard :</u>

New radius will be = 11.5 + 2 = 13.5 yard

Combined\  area =\pi r^{2} \\

                         =3.14\times13.5\times13.5=572.265\ square\ yard

Now, area of the​ walk = Combined area of pool and walk - Area of the pool

                                     = 572.265 - 415.265

                                     = 157 square yards

Therefore, area of the​ walk is 157 square yards.

4 0
3 years ago
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