Ask question

Ask question

All categories

3 years ago

12

Which point is located at (–1, 3)? On a coordinate plane, point A is 1 unit to the right and 3 units down. Point B is 3 units to

the left and 1 unit up. Point C is 1 unit to the left and 3 units up. Point D is 3 units to the right and 1 unit down. A B C D

1 answer:

Marizza181 [45]3 years ago

4 0

Answer:

Point C.

Step-by-step explanation:

When the x-value is negative, the point is moving left. In this case, the point is moving left 1.

When the y-value is positive, the point is moving up. In this case, the point is moving up 3.

Only Point C fits the description.

You might be interested in

PLS HELP ASAP I DONT HAVE TIME AND IT ALSO DETECT IF ITS RIGHT OR WRONG!

KatRina [158]

Answer:

37.5%

Step-by-step explanation:

I don't have a step-by-step explanation, and I don't know if this is right. It doesn't give me enough time to solve it. If an expert could check this, it would be highly appreciated!

3 0

2 years ago

What is the GCF of the<br>following polynomial?<br>10x2 + 45x - 25

Galina-37 [17]

Answer:

5

Step-by-step explanation:

Find the prime factors of each term in orer to find the GCF

8 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle is 1 centimeter longer than one side and 4 centimeters longer than three times the other side

snow_tiger [21]

Answer:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

Step-by-step explanation:

Represent:

The opposite with a
The adjacent with b
The hypotenuse with c

Given that:

$c = 1 + a$

$c = 4 + 3b$

Required

Solve for a, b and c

$c = c$

So, we have:

$1 + a = 4 + 3b$

Subtract 1 from both sides

$a = 4 -1 + 3b$

$a = 3 + 3b$

Apply Pythagoras Theorem

$c^2 = a^2 + b^2$

Substitute 3 + 3b for a and 4 + 3b for c

$(4 + 3b)^2 = (3 + 3b)^2 + b^2$

Open brackets

$16 + 12b+12b+9b^2 = 9 + 9b+9b+9b^2 +b^2$

$16 + 24b+9b^2 = 9 + 18b+10b^2$

Collect Like Terms

$10b^2 - 9b^2 + 18b - 24b + 9 - 16 = 0$

$b^2 - 6b -7 = 0$

Expand

$b^2 +b-7b-7=0$

Factorize:

$b(b+1)-7(b+1) =0$

$(b-7)(b+1) = 0$

Split:

$b - 7 = 0\ or\ b+1=0$

$b = 7\ or\ b=-1$

But the adjacent of a triangle can't have a negative measurement.

So:

$b = 7$

Recall that:

$c = 4 + 3b$

$a = 3 + 3b$

Substitute 7 for b in the above expressions

$c = 4 + 3 * 7$

$c = 4 + 21$

$c = 25$

$a = 3 + 3 * 7$

$a = 3 + 21$

$a = 24$

Hence, the dimensions of the triangle are:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

5 0

3 years ago

PLEASE HELP !! BRAINLIEST AND 10 POINTS

Bumek [7]

POINT A I had the same question in my math class !!!

8 0

3 years ago

Hey guys i really need help pls dont waste the points i actually want help to understand how to solve equations like:

tamaranim1 [39]

Answer:

your question is unclear

Step-by-step explanation:

x+2y=4

-x -x

2y=4-x

divide by 2 to get y by it's self

y=2-(1/2x)

x+2y=4

-2y -2y

x=4-2y

i don't know if u want me to help u with the second one but i did it the first one

3 0

2 years ago