Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If
of a page occupies 1 kB of memory, we can calculate how much memory a book will take

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.
Answer:
#include <iostream>
using namespace std;
int main() {
int *ip_arr,n;//pointer name inp_arr and integer n to store the size.
cin>>n;//size.
for(int i=0;i<n;i++)
ip_arr[i]=-1;//assigning -1 to every element.
for(int i=0;i<n;i++)
{
cout<<ip_arr[i]<<" ";//printing every element.
}
return 0;
}
output:-
100
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1
Explanation:
I am taking input of size.You should enter 100 for 100 values which have value -1.
Answer:
C. deriving benefits from highly focused and high technology markets
Explanation:
Firms that engage in cost-leadership approach seek to combine a low per-unit income with large sales for profit making purposes. Typically, but not always, they are more inclined to market their products and services to a large population base or a niche with a high demand volume. While differentiation enables a company to accomplish a competitive advantage. A Competitive advantage enables a company to achieve more strides over other companies offering related product substitutes. It is an important marketing process that is of critical economic importance to a business.
It should be noted that deriving benefits from highly focused and high technology markets is not part of the approaches to combining overall cost leadership and differentiation competitive advantages.
Answer: Hierarchical structure
Explanation:
The hierarchical structure is the most preferred structure for an organisation. As more and more people join an organisation with the passage of time we can clearly see the different links between the persons and the their hierarchical level to the organisation. In this process it becomes easier to manage the people at the various levels.