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artcher [175]
3 years ago
15

Clint is in study hall reading The hunger games. After 20 minutes, he is on page 151. After 45 minutes, he is on page 181. How m

any pages had Clint read prior to study hall
Mathematics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

The number of pages had Clint read prior to study hall were <u>127 pages</u>.

Step-by-step explanation:

Given:

Clint after 20 minutes is on page 151.

And, after 45 minutes he is on page 181.

Now, to find the pages Clint read prior to study hall.

<em>The time difference = 45 minutes - 20 minutes.</em>

<em>                                  =  25 minutes.</em>

<em>Difference between the pages = 181 - 151</em>

<em>                                                     =  30 pages.</em>

If Clint is reading each page at same speed.

Then, in 25 minutes he can read = 30 pages.

So, in 1 minute he can read = 30 ÷ 25 = 1.2 pages.

Thus, in 20 minutes he can read =1.2\times 20

                                                         =24 pages.

Now, number of pages Clint had read prior to study hall = 151 - 24

                                                                                              =  127 pages.

Therefore, the number of pages had Clint read prior to study hall were <u>127 pages</u>.

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Light A flashes every 2 minutes while light B flashes every 7. The goal is to figure out when both lights flash at the same time and then figure out the other part later. You have to find the common multiples of 7 and 2. Meaning that you have to find out which number can they both be multiplied into. In this case, it is 14 because 7 can be multiplied by 2 to get 14 and 2 can be multiplied by 7. So if every 14 minutes they flash together at the same time, now you need to find out what time AFTER 3 will they both flash. You know that they both flashed at 1:00 so they will flash again at 1:14 and 1:28 and so on, but you need to find out when is the soonest they will flash after 3. 2 hours after the 1:00 flash will be 3:00 so that is 120 minutes. 120 minutes divided by 14 minutes comes to 8.5 but you dont need the decimal. Just simply multiply 14 by 8 and that comes to 112 minutes and if you add that to 1:00 you get 2:52. so they flashed at 2:52 so the next time they flash will be 14 minutes after 2:52. Sorry for the super long answer
6 0
3 years ago
Seven times a number is less than or equal to a quantity that is 24 less than that same
Ad libitum [116K]

Answer:

7x\leq x-24

Here, x denotes the required number.

Step-by-step explanation:

Let x denotes the required number that satisfies the following condition.

''seven times a number is less than or equal to a quantity that is 24 less than that same  number''

Seven times a number is equal to 7x

Quantity that is 24 less than that same  number is equal to x-24

Now find the inequality.

As seven times a number is less than or equal to a quantity that is 24 less than that same  number,

7x\leq x-24

6 0
3 years ago
In a candy box, there are 5 times as many candies with nuts as candies without nuts. There are 18 candies in the box. How many c
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in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

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\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

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In a horse race, the odds in favor of the first horse winning in an 8-horse race are 2 to 5. The odds against the second horse w
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The probability that the first horse wins is 2/7. The probability that the second horse wins is 3/10. Since the events that the first horse wins and the second horse wins are shared exclusive, the probability that either the first horse or the second horse will win is :

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Hope this is correct.

4 0
3 years ago
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