Answer:
Number of times an event occurs total number an experiment is performed
Step-by-step explanation:
A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer:
Step-by-step explanation:
Hello there!
The first thing we want to do is find the least common denominator which would be 20
so we multiply the denominator and numerator of the fractions on the left side by 4
3x4=12
5x4=20 -12/20x
1x4=4
5x4=20 so now we would have
once again we want to isolate the variable using inverse operations
to get rid of the 4/20 we subtract each side by 4/20
now we have
now we want to get rid of the -12/20
to do so we divide each side by -12/20 (or -.6 as a decimal to make it easier)
REMEMBER flip the equality sign
we're left with
First you must find the unit rate, so a 45 divided by 6 is 7.5, so then, multiply that by 10, 10 times 7.5 is 75, move the decimal place up, now you have the base rate, you can find any amount, so with these questions, all you must do is find the unit rate, in this case, the unit rate is 7.5, the unit rate will always be the ratio of one unit to the value of the unit, seen as ( 1-7.5 ) here.
Hope this helps, if not, comment below please!!!
Answer:
Step-by-step explanation:So to find it you need to eliminate either x or y. 2x-5y=10 over 4x-10y=20. In order to get y to eliminate you need one equation to have a positive 10y and a negetive 10y. So you multiply both sides of the first equation by negetive 2 so it is now, -4x+10y=-20. Notice how all the numbers in both equations are opposite this gives us ims infinitaly many sollutions. So it is not A. Or b it will do the same thing. The answer is either D or C hope this helps
