Well, lets look at it this way ... tell me if this does anything for you:
-- Take the number 31.01 .
-- Stick a zero on the end and make it 31.010 .
-- Zeros at the end of a number after the decimal point don't change
the value of the number. So you haven't changed the value of 31.01 .
-- But now it looks exactly like the other number !
-- They must be equal.
Does this float your boat at all ?
P of a rectangle= 2l + 2w
P = 2(48) + 2(20)
P= 96 + 40
P= 136m
The length of the rectangle is 136 meters.
I hope that helped.
The answer is 93 to 31 :)
Answer:
Arc length is ![\dfrac{3\pi }{4}\ \text{inches}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%5Cpi%20%7D%7B4%7D%5C%20%5Ctext%7Binches%7D)
Step-by-step explanation:
We have,
Central angle is 15 degrees and the radius of the circle measures 9 inches.
It is required to find the arc length of the sector.
The relation between arc length and the central angle is given by :
![\dfrac{\text{arc length}}{\text{circumference}}=\dfrac{\theta}{360}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7Barc%20length%7D%7D%7B%5Ctext%7Bcircumference%7D%7D%3D%5Cdfrac%7B%5Ctheta%7D%7B360%7D)
Circumference, ![C=2\pi r=18\pi](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r%3D18%5Cpi)
![\theta=15^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D15%5E%7B%5Ccirc%7D)
![\dfrac{x}{18\pi }=\dfrac{15}{360}\\\\\dfrac{x}{18\pi }=\dfrac{1}{24}\\\\x=\dfrac{18\pi }{24}\\\\x=\dfrac{3\pi }{4}\ \text{inches}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B18%5Cpi%20%7D%3D%5Cdfrac%7B15%7D%7B360%7D%5C%5C%5C%5C%5Cdfrac%7Bx%7D%7B18%5Cpi%20%7D%3D%5Cdfrac%7B1%7D%7B24%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B18%5Cpi%20%7D%7B24%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B3%5Cpi%20%7D%7B4%7D%5C%20%5Ctext%7Binches%7D)
Hence, the correct option is (b).