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shusha [124]
3 years ago
12

Patrick raced round a 440 metre circular track and stopped suddenly after 900 metres . How far was she from the starting point a

t the 900 metre mark ? Solve
Mathematics
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be 900-880=20 meters from the starting point.

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Triangle rst is dilated by a scale factor of 5 to form triangle r's't'. side r's' measures 40. what is the measure of side rs?
LenKa [72]

Answer: 8

Step-by-step explanation:

We know that scale factor = (image)/(preimage).

Substituting in what we have,

5=\frac{R'S'}{RS}\\\\5=\frac{40}{RS}\\\\RS=\boxed{8}

5 0
2 years ago
What is the answer to 4x + 27
Alla [95]

Answer:

Step-by-step explanation:

4x+27

----  ----

4       4

x=6.75 or x=7

7 0
3 years ago
A recursive formula for the sequence 18,9,4.5,... is
dybincka [34]

Answer:

A1 = 18

A(n) = A (n-1) -2

Step-by-step explanation:

N represents the number in a sequence and the difference in the sequence is -2 since each time the number is listed in the sequence it is divide by 2.

3 0
2 years ago
Jada was using square stickers that were 3/4in long to decorate the spine of a photo album. The spine is 10 and 1/2in long. If s
nevsk [136]

Answer:

13

Step-by-step explanation:

Given:

  1. Square stickers that were 3/4 in long
  2. The spine is 10 and 1/2 in long

If she laid the stickers side by side without gaps or overlaps so the number of sticker to cover the length of the spine:

\frac{The length of the spine}{the length of the sticker}

10 : \frac{3}{4} ≈13  

She needs 13 stickers cover the length of the spine

7 0
4 years ago
Read 2 more answers
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
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