Patrick raced round a 440 metre circular track and stopped suddenly after 900 metres . How far was she from the starting point a
1 answer:
Answer:
20 meters
Step-by-step explanation:
The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.
So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.
The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be meters from the starting point.
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Answer:
The area of the shaded region is about 58.9 square inches.
Step-by-step explanation:
To solve this question, let's recall some facts.
We know that the area of a circle can be defined as the following:
where r is the radius of the circle.
We too know that circles have a diameter and a radius. The diameter of a circle is the distance a line that connects two points on a circle with its center, and the radius is half of the diameter.
We also know that figures can touch each other, or be in tangent with each other. For the sake of simplicity, we're going to assume that the shaded circles are in tangent with each other, or touch each other. Because they touch each other, these three circles can share 5 in. of the 15 in. rectangle. This means that the circles are 5 in. in diameter, or 2.5 in in radius.
Now, we can solve the problem.
Because we have 3 circles, each with 2.5 in. radii, we can have the following expression which represents the total area of these circles:
After approximation, I can conclude that the area of the shaded region is 58.9 square inches.
Answer:
a
Step-by-step explanation:
Solving the inequality
>
+ 1
Multiply through by 12 ( the LCM of 6 and 4 ) to clear the fractions
2(x + 3) > 3x + 12
2x + 6 > 3x + 12 ( subtract 2x from both sides )
6 > x + 12 ( subtract 12 from both sides )
- 6 > x , that is
x < - 6
The only value less than - 6 is - 10
Thus x = - 10 is a solution to the inequality