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2 years ago

Asnwer aswer answer answer plz ASWER ANSWER ANSWER ANSWERR PLZ ANSWEER I NEED ANSWER PLZZZZZ!!!! i need help HELP!!!

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

7 0

Answer:

29,035.43 meters

Step-by-step explanation:

What we know:

- The elevation of the shore of the Dead Sea is -1,344.99 meters.

- The summit of Mt. Everest is 30,380.42 meters above the Dead Sea.

So, we just add the two values.

30,380.42 + (-1,344.99)

We can rewrite this as 30,380.42 - 1,344.99 since adding a negative is the same as subtracting that number.

And we get 29,035.43 meters as the elevation or height of Mt. Everest.

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tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.35$ estimated proportion (value assumed)

$p$ true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586$

And rounded up we have that n=350

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