Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
14. The equation would be -16t^2+60t+7 To find the maximum point plug in values into the equation -b/2a to find the axis of symmetry, and plug that number in for t.
b=60, a=-16
-60/-32=t=1.875
-16(1.875)^2+60(1.875)+7=63.25
Maximum point: (1.875,63.25)
The ball will land after about 3.86 seconds
Step-by-step explanation:
Equation 1

Equation 2

450/3 = x.
150 = x.
So x = 150.
This means 45 is 30% of 150