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2 years ago

Arianna deposits $500 in an account that pays 1.3% interest, compounded semi-annually. How much is in the

Mathematics

1 answer:

Alika [10]2 years ago

5 0

Answer:

1•3 × $500

100

1.3 × 10 × $500

100× 10

13 × $500

1000

=$6.5 semi annually

end of two years.....

6.5 × 4

=$26

in account.....

$500+$26

=$526

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The sum of Jim's weight and Bob's weight is 180 pounds. If you subtract Jim's weight from Bob's weight, you get half of Bob's we

Furkat [3]

Answer:

120 pounds

Step-by-step explanation:

We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:

j + b = 180

b - j = 1/2b

Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)

$b - j = \frac{b}{2}\\\frac{b}{2} - j = 0$

Now we can solve using the process of elimination.

$b + j = 180\\\\\frac{b}{2} - j = 0\\\\b + \frac{b}{2} = 180\\\\b + b \cdot 2 = 180\cdot 2\\3b = 360\\b = 120$

Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.

$120 + j = 180\\j = 180-120\\j = 60$

So Bob weighs 120 pounds and Jim weight 60 pounds.

Hope this helped!

4 0

3 years ago

Read 2 more answers

Geometry math question no Guessing and Please show work

Alona [7]

Well, if point C is dilated by 5/3, C' should be (3*5/3, -6*5/3)

This is equivalent to Option A, (5, -10)

3 0

3 years ago

A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe

PSYCHO15rus [73]

Answer:

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2 bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

let A = (u - E) * ( $\sqrt{n}$ / s) be the test statistic

we want P( average_l < A < average_u ) = 95%

look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test

average_l = -1.96 which corresponds to the 2.5%

average_u = 1.96

P( -1.96 < A < 1.96) = 95%

P( -1.96 < (u - E) * ( $\sqrt{n}$ / s) < 1.96) = 95%

Solve for the true mean E ok

E < u + 1.96* (s / $\sqrt{n}$ )

from -1.96 < (u - E) * ( $\sqrt{n}$ / s)

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 518.7197348105429466

upper bound is 26,744.9197

u - 1.96* (s / $\sqrt{n}$ ) < E

26,226.2 - 518.7197348105429466 < E

25,707.48026519 < E

lower bound is 25,707.48026519

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

7 0

3 years ago

Mahra saw an ad for three t-shirts for $33 and four t-shirts costing $42. Is the relationship of price and number of t-shirts a

slamgirl [31]

Answer

no because as per the first ad the rate of a shirt is 11 dollars wherelse if u take second one its 2 dollars lesser

Step-by-step explanation:

1 shirt=33/3

=11

11*4=44

*=multiplication

4 0

3 years ago

I dont understand this can someone help me

LiRa [457]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers