1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natasha_Volkova [10]
3 years ago
11

2x2= please get it right

Mathematics
2 answers:
NemiM [27]3 years ago
7 0

Answer:

the answer is 4  

Step-by-step explanation:

2+2=4 or 5-1=4

d1i1m1o1n [39]3 years ago
5 0

Answer:

2x2 is equal to 4 for sure

You might be interested in
Point)<br> Complete the missing value in the solution to the equation:<br> 6x + x = y + 2x<br> (3,
AleksandrR [38]

Answer:

-2

Step-by-step explanation:

8 0
3 years ago
Given: m || n<br><br> What is the value of x?
Hoochie [10]
6x-2=46;6x=48;x=8
Therefore, x is equal to 8
4 0
4 years ago
Read 2 more answers
How many people can ride in 1 car?
hjlf

Answer:

6 people

Step-by-step explanation:

take the 18 and divide it by three because this will help you solve for one car so 18 divided by three is six

6 0
3 years ago
A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia
Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which <em>k</em> items can be selected from <em>n</em> different items without replacement and  irrespective of the order.

{n\choose k}=\frac{n!}{k!(n-k)!}

Permutation is a mathematical procedure to determine the number of arrangements of <em>k</em> items from <em>n</em> different items respective of the order of arrangement.

^{n}P_{k}=\frac{n!}{(n-k)!}

In this case we need to select two different cards from a pack of 52 cards.

  • Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{52\choose 2}=\frac{52!}{2!(52-2)!}

      =\frac{52\times 51\times 50!}{2!\times50!}\\=1326

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

  • Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

^{n}P_{k}=\frac{n!}{(n-k)!}

^{52}P_{2}=\frac{52!}{(52-2)!}

       =\frac{52\times 51\times 52!}{50!}

       =52\times 51\\=2652

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0
3 years ago
Zach's chemistry textbook weighs 2/3 of a pound and his geometry textbook weighs 1/3 of a pound. How much more does the chemistr
gizmo_the_mogwai [7]
2/3 lb. - 1/3 lb. = 1/3 lb.
check: 1/3 lb. + 1/3 lb. = 2/3lb
ANSWER 》1/3 lb. MORE
5 0
3 years ago
Other questions:
  • Please help me!!!!!!!!!!!!!!!!!!!
    13·1 answer
  • Whitout solving, whag can you tell about the solution to this equation? 1/2(b+14)=b+14/2
    11·2 answers
  • An electrician charges $40 to come to your house she also charges $55 for each hour that she works the electrician charges you a
    11·1 answer
  • In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
    14·1 answer
  • Evaluate 9P4. Please I<br> Need a good grade! Thanks
    7·2 answers
  • Please do it in substitution method. Thanks.​
    13·1 answer
  • Could u help me out with this question? It involves SIN COS TAN (SOH CAH TOA)
    8·1 answer
  • If y=1/2*x+3, which ordered pair is one of the solutions for the equation and the coordinates for one of the points on
    7·1 answer
  • Im having touble finding this answer because it says i keep getting it wrong
    15·1 answer
  • ΔAXY is similar to ΔABC.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!