Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way
Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u> 18 10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
The lowest is the square root of 9 which is 3. After that is 3.15, 13/4 (3.25), 3 1/2 (3.50). My explanation would be: first I found out the square root of 9. Then divided 13 by 4.
Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
A= πr² = π × 6² = "113.1" is the area of the frisbee.
Please put me as brainliest.
Answer:
Option: C is the correct answer.
C. Periodic with period 4 and amplitude of about 15.
Step-by-step explanation:
We are given the table of values as:
Hour 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11
Number 24-41-10-32-26-38-9-31-25-39-12
of boats
As we could see that after every 4 value the values are approximately repeating.
Hence,the data set is approximately periodic.
Also, the amplitude is calculated as:
Average of the maximum and minimum value of each set
We divide the set into 3 sets as follows:
Hour 1 2 3 4
Number of boat 24 41 10 32
Here we have amplitude as:
(41-10)/2=15.5
Hour 5 6 7 8
Number of boat 26 38 9 31
Amplitude is:
(38-9)/2=14.5
Hour 9 10 11 12
Number of boat 25 39 12
Amplitude is:
(39-12)/2=13.5
Hence, we see that the amplitude is about 15.