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djyliett [7]
3 years ago
9

she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, wh

at is the probability that it will be cherry? Round to the nearest hundredth.
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:     \dfrac{1}{2}

Step-by-step explanation:

We know that probability for any event = \dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3=  12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}

Hence, the  probability that it will be cherry is \dfrac{1}{2} .

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We need to find the probability of the card chosen at random is yellow or brown.

So, since there are 3 yellow cards and 7 brown cards, the total numbers of cards that are yellow or brown is:

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Now, the probability that the chosen card is yellow or brown can be found by dividing the above value by the total number of cards in the box.

The total number of cards in the box is:

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Thus, that probability is given by:

\frac{10}{12}=\frac{10\div2}{12\div2}=\frac{5}{6}

Therefore, the answer is:

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