Question

she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry? Round to the nearest hundredth.

Answer 1

Answer:     $\dfrac{1}{2}$

Step-by-step explanation:

We know that probability for any event = $\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3=  12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

$\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}$

Hence, the  probability that it will be cherry is $\dfrac{1}{2}$ .