Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
Answer would be A. -4(7x-9)
The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.
Step-by-step explanation:
Let,
Cost of one plain wrapping paper = x
Cost of one holiday wrapping paper = y
According to given statement;
6x+y=62 Eqn 1
3x+10y=164 Eqn 2
Multiplying Eqn 2 by 2
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 19
Putting y = 14 in Eqn 1
Dividing both sides by 6
The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.
Keywords: linear equation, elimination method
Learn more about linear equations at:
#LearnwithBrainly
In order to calculate left chain, you need to subtract that as follows:
Left chain = 3 5/12 - 2 1/3
L.C. = 41/12 - 7/3
L.C.= 41-28 / 12
L.C. = 13/12
In short, Your Answer would be 13/12 feet or 1 1/12 feet
Hope this helps!
39/120 = x / 1800....39 choc. chip to 120 students = x choc. chip to 1800 students
now we cross multiply because this is a proportion
(120)(x) = (39)(1800)
120x = 70200
x = 70200/120
x = 585 <===
or u could do it this way as well...
39 out of 120 picked chocolate chip....
39/120 = 0.325 = 32.5%....so 32.5% chose chocolate chip.
32.5% of 1800 = 0.325(1800) = 585 <==
