Question

Carlos and Kristin are selling wrapping paper for a school fundraiser. Customers can buy rolls of

Answer 1

The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.

Step-by-step explanation:

Let,

Cost of one plain wrapping paper = x

Cost of one holiday wrapping paper = y

According to given statement;

6x+y=62    Eqn 1

3x+10y=164    Eqn 2

Multiplying Eqn 2 by 2

$2(3x+10y=164)\\6x+20y=328\ \ \ Eqn\ 3$

Subtracting Eqn 1 from Eqn 3

$(6x+20y)-(6x+y)=328-62\\6x+20y-6x-y=266\\19y=266$

Dividing both sides by 19

$\frac{19y}{19}=\frac{266}{19}\\y=14$

Putting y = 14 in Eqn 1

$6x+14=62\\6x=62-14\\6x=48$

Dividing both sides by 6

$\frac{6x}{6}=\frac{48}{6}\\x=8$

The cost of one roll of plain wrapping paper is $8 and one roll of holiday wrapping paper is $14.

Keywords: linear equation, elimination method

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