Answer:
ñ
Step-by-step explanation:
ññññññ
ñññññññññññññññññññññ
6 times 3/8 is the same as:
<span>6/1 * 3/8 </span>
<span>Now, multiply the tops and bottoms to get: </span>
<span>18/8 </span>
<span>We can divide the top and bottom by 2, giving us: </span>
<span>9/4</span>
Well,
we know that we need to accumulate points from x and y to reach 20 points.
since x provide 3 and y provide 4 points, the formula would be :
3x + 4y = 20
or it can be written as :
y = (3x/4)+5
hope this helps
The answer is 7.
Hope this helps.
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
