Answer:
7x + 2y = 1
Step-by-step explanation:
1. Find the slope of the line.
(y2-y1)/(x2-x1) ----> (11 - (-3))/((-3) -1) ----> (11+3)/ (-3 -1) ----> 14/-4
*lets simplify into (7/-2)*
2. Write into slope intercept form.
y=mx+b (m is the slope) (b is the y intercept)
y = (7/-2)x + b
We now need to find the value of b, this can be done by plugging in values of x and y, and using algebra to solve.
11 = (7/-2)(-3) + b
11 = 10.5 + b
b = 0.5 or 1/2
slope intercept form y = (7/-2)x + 1/2
Now we convert to standard form: ax+by=c
*In this form we our a term cannot be a fraction nor can it be negative*
1. Get x and y on the same side, and since our x term is negative right now, we can make it positive by adding it on both sides.
(7/2)x + y = 1/2
2. We now want to get rid of the fraction in term a, so we multiply the entire function by two, so the denominator cancels out.
2(7/2)x + 2y = 2(1/2)
Simplify and you get
7x + 2y = 1
Answer:
9/25 i think
Step-by-step explanation:
i got 9 from the tally marks, there was 9 tally marks,
and 25 is how much a quarter is
The Line passes through -7 on the y axis and slants up witha slope of 3
6/12 can be reduced to 1/2.
6/6=1
12/6=2
Answer: 1 van can hold 18 people, and 1 bus can hold 53 people.
What we know: Class A rented 2 filled vans and 7 buses with 407 students.
Class B rented and filled 1 van and 7 buses with 389 students.
What we need to know: How many students can a van carry? How many students can a bus carry?
Equation A: 2v + 7b = 407
Equation B: 1v + 7b = 389
Variables used: v = amount of people that can fill a van and b = amount of people that can fill a bus
This is quite a simple equation, because we know that class A used 1 more van than Class B, and the question says that each vehicle was full. So, all you have to do it subtract 389 from 407 to get 18. That means that 1 can can hold 18 people.
Now you just plug it in to find the value for b, 1(18) + 7b = 389
7b = 371
b = 53
So the amount of people that can fit on a van is 18, and the amount of people that can ft on a bus is 53.
