We have three numbers to arrange so that 6 is 1/10 of the value of the other six.
Since position tells us whether we're talking about single, tens, hundreds, thousands (e.g. 25 is two times 10 plus five times 1) we know that the two sixes must be next to each other.
This leaves us with two options. 663 or 366.
In each of these cases the second 6 in the number is one tenth of the first 6.
If we look at the only other option: 636 we see that the second 6 is one hundredth of the value of the first 6.
6y+1>=10 Subtract 1 from both sides 6y>=9 Divide 6 on both sides so that the only thing remaing on the left side is the variable y. Final Answer: y>= 1.5 or 1 1/2
