Write the equation of an ellipse with the following characteristics: center =(1,-3) vertices=(-6,-3),(8,-3)
2 answers:
Answer:
(x-1)²/49 + (y+3)²/16.51 = 1
Step-by-step explanation:
vertex (8,-3) Foci (6.7,-3) center (h,k) = (1,-3) , major axis parallel to x axis
a is the distance of the vertex from the center, and c is the distance of the foci from the center. b is semi-minor axis
b² = a² - c² Ellipse equation: (x-h)²/a² + (y-k)²/b² = 1
a = 8-1 = 7 c = 6.7 - 1 = 5.7
b² = 7² - 5.7² = 16.51
Ellipse equation: (x-1)²/49 + (y- -3)²/16.51 = 1 i.e. (x-1)²/49 + (y+3)²/16.51 = 1
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Answer:
three consecutive odd integers are.
Step-by-step explanation:
Let x be the first term of odd integer,
Therefore, the second consecutive odd integers =
Similarly, the third consecutive odd integers =
Given:
The sum of the first term and second term is 344.
first term + second term = 344
Here first term is x and second term is .
Therefore, the first odd integers is 171.
And the second consecutive odd integers =
Similarly, the third consecutive odd integers =